Longest Substring with At Most K Distinct Characters
update 2018-10-18 16:09:53
Given a string, find the length of the longest substring T that contains at most k distinct characters.
Example 1:
Input: s = "eceba", k = 2
Output: 3
Explanation: T is "ece" which its length is 3.
Example 2:
Input: s = "aa", k = 1
Output: 2
Explanation: T is "aa" which its length is 2.
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Basic Idea:
利用sliding window的思路,维持一个hashmap记录窗口内每个字母的个数,如果map的大小超过k,则left向右移动,更新map,直到大小变为k. 解就是窗口size的最大值。
Java Code:
class Solution {
public int lengthOfLongestSubstringKDistinct(String s, int k) {
Map<Character, Integer> map = new HashMap<>();
int ret = 0, left = 0, right = 0;
for (right = 0; right < s.length(); ++right) {
char c = s.charAt(right);
map.put(c, map.getOrDefault(c, 0) + 1);
if (map.size() > k) {
// shrink left to make size == k
while (map.size() > k) {
char last = s.charAt(left);
if (map.get(last) == 1) {
map.remove(last);
} else {
map.put(last, map.get(last) - 1);
}
left++;
}
}
ret = Math.max(ret, right - left + 1);
}
return ret;
}
}